PadhoNaby JEE Master
  • Home
  • Learn
  • Plan & Focus
  • Community
  • Pricing
  • Play & Compete
  • Free Resources
Log inJoin Free
PadhoNaby JEE Master

Ask. Share. Learn. Grow Together. India's all-in-one community for JEE Main & JEE Advanced aspirants.

Explore

  • Learn
  • Plan & Focus
  • Community
  • Play & Compete
  • Free Resources

Resources

  • JEE Main PYQs
  • JEE Advanced PYQs
  • Formula Sheets
  • NCERT Mapping
  • Mock Analysis

Support

  • Help Center
  • Privacy Policy
  • Terms of Use
  • Contact Us

© 2026 PadhoNa. All rights reserved.

Formula Sheets / Physics

Chapter 13

Thermal Properties of Matter

Revise with flashcards Download this chapter (PDF) All Physics formulas (PDF)
Thermal expansionCalorimetry and specific heatHeat transfer

Thermal expansion

  • ΔL=LαΔT,ΔA=AβΔT,ΔV=VγΔT
  • α:β:γ=1:2:3
  • Pendulum clock

    Δt=21​αΔT×t (time lost per t when hotter)
  • Temperature scales

    100C​=180F−32​=100K−273.15​

Calorimetry and specific heat

  • Q=mcΔT,Q=mL,heat lost=heat gained

Heat transfer

  • Conduction

    dtdQ​=LKAΔT​,Rth​=KAL​
  • Series and parallel

    R=R1​+R2​ (series),R1​=R1​1​+R2​1​ (parallel)
  • Stefan–Boltzmann

    P=eσAT4;Pnet​=eσA(T4−T04​)
  • Wien's law

    λm​T=b≈2.9×10−3 m K
  • Newton's law of cooling

    dtdT​=−k(T−T0​);tT1​−T2​​≈k(2T1​+T2​​−T0​)
Mechanical Properties of FluidsThermodynamics